Bromothymol Blue Experiment

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An experiment was conducted to investigate the inputs of carbon dioxide and sunlight drives the process of photosynthesis.

Figure 1. clearly demonstrates the presence of an irregular pattern of disc floating after 8 minutes, all deeply infiltrated with Sodium bicarbonate. According to the outcomes, there was an absence of disc floating in the first 2 minutes of the experiment, hence no disc have been infiltrated with sodium bicarbonate. As observed, after 3 minutes the number of disc floating were constantly increasing until it reaches the 8 minute mark as all 20 disc were fully floating. Hence, at 8 minutes Group Three have perceived the presence of all floating disc, indicating that they have all been fully infiltrated with Sodium Bicarbonate. In addition, Figure 1. displayed that at exactly 5 minutes, 10 disc were floating, …show more content…
Thus, this indicates that less carbon dioxide were present in this solution post-experiment. In contrast, Flask 2 demonstrates no or very minor changes in the initial and final colour of Bromothymol Blue. Hence, this displays that the final and initial quantity of carbon dioxide have not altered.

According to Figure 8, a constant repetition amongst the class results of the final colour of Bromothymol Blue for both Flask 1 and 2. As perceived from the table, all groups obtain a darker shade when Flask 1 is placed in Light. However, on the contrary, Flask 2 (which was placed in the dark) all observe a lighter shade in comparison to Flask 1. This observation indicates that in Flask 1, a significant decrease in carbon dioxide levels have been demonstrated as all group notice a visibly darker shade. On the other hand, Flask 2 display a consistent observation of lighter shaded colours. This shows that while in the dark, the level of carbon dioxide have remained constant through
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