Case Solved By: Glavin Wiechert
Date: Thursday April 28, 2011
Teacher: Louth, Ellen Mary
Class: Chemistry 11 Ad
Site:
In a 100 g sample:
37.01%C
> 37.01g x [1 mol / 12.01] ==> 3.08 mol
2.2%H > 2.2g x [1 mol / 1.01] ==> 2.18 mol
18.5%N
> 18.5g x [1 mol / 14.01] ==> 1.32 mol
42.27%O
> 42.27g x [1 mol / 16.0] ==> 2.64 mol
Divide by Lowest: ( ÷1.32)
C
3.08/1.32 ==> 2.33
H
2.18/1.32 ==> 1.65
N
1.32/1.32 ==> 1.0
O
2.64/1.32 ==> 2.0
Formula of Compound:
C2.33 H1.65 N1.0 O2.0
⇒
C
H
N
O
→ Trinitrotoluene (Explosive TNT [dynamite])
7
5
3
6
Passengers:
1. Location: Blood
In a 100 g sample:
67.31%C
> 67.31g x [1 mol / 12.01] ==> 5.6 mol
6.98%H
> 6.98g x [1 mol / 1.01] ==> 6.91 mol
4.62%N
> 4.62g x [1 mol / 14.01] ==> 0.33 mol
21.1%O
> 21.1g x [1 mol / 16.0] ==> 1.32 mol
Divide by Lowest: ( ÷0.33)
C
5.6/0.33 ==> 16.97
H
6.91/0.33 ==> 20.94
N
0.33/0.33 ==> 1.0
O
1.32/0.33 ==> 4.0
Formula of Compound:
⇒
C
H
NO → Cocaine (illegal narcotic)
17
21
4
2. Location: Face
In a 100 g sample:
63.15%C
> 63.15g x [1 mol / 12.01] ==> 5.26 mol
5.3%H
> 5.3g x [1 mol / 1.01] ==> 5.25 mol
31.55%O
> 31.55g x [1 mol / 16.0] ==> 1.97 mol
Divide by Lowest: ( ÷1.97)
C
5.26/1.97 ==> 2.67
H
5.25/1.97 ==> 2.66
O
1.97/1.97 ==> 1.0
Formula of Compound:
C2.67 H2.66 O1.0 x 3
⇒
C
H
O3 → Vanilla (flavouring)
8
8 Location: Stomach
In a 100 g sample:
46.66%C
> 46.66g x [1 mol / 12.01] ==> 3.89 mol
4.48%H
> 4.48g x [1 mol / 1.01] ==> 4.44 mol
31.10%N
> 31.1g x [1 mol / 14.01] ==> 2.22 mol
17.76%O
> 17.76g x [1 mol / 16.0] ==> 1.11 mol
Divide by Lowest: ( ÷1.11)
C
3.89/1.11 ==> 3.5
H
4.44/1.11 ==> 4.0
N
2.22/1.11 ==> 2.0
O
1.11/1.11 ==> 1.0
Formula of Compound: C3.5 H4.0 N2.0 O1.0
⇒
C
H
N
O
→ Thiobromine (Flavouring [chocolate])
7
8
4
2 3.
Location: Pockets (2000 tablets)
In a 100 g sample:
72.15%C
> 72.15g x [1 mol / 12.01] ==> 6.01 mol
7.08%H
> 7.08g x [1 mol / 1.01] ==> 7.01 mol
4.68%N
> 4.68g x [1 mol / 14.01] ==> 0.33 mol
16.03%O
> 16.03g x [1 mol / 16.0] ==> 1.0 mol
Divide by Lowest: ( ÷0.33)
C
6.01/0.33 ==> 18.21
H
7.01/0.33 ==> 21.24
N
0.33/0.33 ==> 1.0
O
1.0/0.33 ==> 3.03
Formula of Compound: C18.21 H21.24 N1.0 O3.03
⇒
C
H
NO → Codeine (painkiller)
18
21
3
4.
Location: Blood and Pockets
In a 100 g sample:
15.87%C
> 15.87g x [1 mol / 12.01] ==> 1.32 mol
2.22%H
> 2.22g x [1 mol / 1.01] ==> 2.2 mol
18.15%N
> 18.15g x [1 mol / 14.01] ==> 1.3 mol
63.41%O
> 63.41g x [1 mol / 16.0] ==> 3.96 mol
Divide by Lowest: ( ÷1.3)
C
1.32/1.3 ==> 1.02
H
2.2/1.3 ==> 1.69
N
1.3/1.3 ==> 1.0
O
3.96/1.3 ==> 3.05
Formula of Compound: C1.02 H1.69 N1.0 O3.05
⇒
C
H
N
O
→ Nitroglycerin (Explosive)
3
5
3
9 5.
Location: Blood
In a 100 g sample:
75.42%C
> 75.42g x [1 mol / 12.01] ==> 6.28 mol
6.63%H
> 6.63g x [1 mol / 1.01] ==> 6.56 mol
8.38%N
> 8.38g x [1 mol / 14.01] ==> 0.60 mol
9.57%O
> 9.57g x [1 mol / 16.0] ==> 0.60 mol
Divide by Lowest: ( ÷0.6)
C
6.28/0.6 ==> 10.47
H
6.56/0.6 ==> 10.93
N
0.6/0.6 ==> 1.0
O
0.6/0.6 ==> 1.0
Formula of Compound: C10.47 H10.93 N1.0 O1.0
⇒
C
H
N
O
→ Strychnine (Rat Poison)
21
22
2
2 Location: Pockets
In a 100 g sample:
37.01%C
> 37.01g x [1 mol / 12.01] ==> 3.08 mol
2.22%H
> 2.22g x [1 mol / 1.01] ==> 2.20 mol
18.50%N
> 18.5g x [1 mol / 14.01] ==> 1.32 mol
42.27%O
> 42.27g x [1 mol / 16.0] ==> 2.64 mol
Divide by Lowest: ( ÷1.32)
C
3.08/1.32 ==> 2.33
H
2.2/1.32 ==> 1.67
N
1.32/1.32 ==> 1.0
O
2.64/1.32 ==> 2.0
Formula of Compound: C2.33 H1.67 N1.0 O2.0
⇒
C
H
N
O
→ Trinitrotoluene (Explosive TNT [dynamite])
7
5
3
6 6.
Location: Pockets
In a 100 g sample:
57.14%C
> 57.14g x [1 mol / 12.01] ==> 4.76 mol
6.16%H
> 6.16g x [1 mol / 1.01] ==> 6.1 mol
