alpha:beta:gamma=0:-b:c
(1)
and radius
R_A=(a^2b^2c^2)/((b+c)|b-c|sqrt(-a^4+2a^2b^2-b^4+2a^2c^2-c^4))R,
(2)
where R is the circumradius of the reference triangle.
ApolloniusCirclesRadicalLine
Because the Apollonius circles intersect pairwise in the isodynamic points, they share a common radical line …show more content…
The vertices of the D-triangle lie on the respective Apollonius