WORKBOOK EXERCISE 23
1. What is the r value for the relationship between Hamstring strength index 60°/s and the Shuttle run test? Is this r value significant? Provide a rationale for your answer.
ANSWER: The obligatory r value is -0.149 and this r value is not significant since the p-value for this correlation coefficient or r is 0.424 which is extra than 0.05 or 0.01 and henceforth at 5% and 10% both level , the null hypothesis of insignificance cannot be rejected and the assumption is the r value is not significant.
2. Consider r = 1.00 and r = −1.00. Which r value is stronger? Provide a rationale for your answer.
ANSWER:…show more content… WORKBOOK EXERCISE 24
1. What is the r value listed for the relationship between variables 4 and 9?
ANSWER: The value of r = -0.32
2. Describe the correlation r = −0.32 using words. Is this a statistically significant correlation? Provide a rationale for your answer.
ANSWER: It characterizes a modest negative relationship among the variables. This is statistically significant at the 1% level of significance as shown in the table. (** p < 0.01)
3. Calculate the percentage of variance explained for r = 0.53. Is this correlation clinically important? Provide a rationale for your answer.
ANSWER: Variance = r^2 = (0.53) ^2 = 0.2809 = 28.1%
The correlation is clinically significant as any variance over 9% is acknowledged as clinically significant.
4. According to Table 2, r = 0.15 is listed as the correlation between which two items? Describe this relationship. What is the effect size for this relationship, and what size sample would be needed to detect this relationship in future studies?
ANSWER: The correlation is among variables 3 and 7. This signifies correlation among Positive Items and Avoidance. Here is a feeble correlation, since r < 0.3. The effect size is 0.15. The sample size needed in this circumstance would be 273 (given a power of 0.8).
5. Calculate the percentage of variance explained for r = 0.15. Describe the clinical importance of this relationship.
ANSWER: Variance =
