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midpoint formula
circle
prove right triangles using isosceles if 2 sides have the same length diagonals have the same midpoint if they bisect each other slope of a line
point slope form
general form
parallel and perp lines are perpendicular if
vert.
horiz.
, parallel if slopes are equal
completing the square quadratic
Chapter 1 it is a function if there is one input, and one or more outputs
domain: “is there anything i can't stick in”, make equal to 0, when in radical it can be 0 and + #, but no , so set inside odd/even/neither: even f(x)=f(x), same on left as right of yaxis, odd f(x)=f(x), same upside down as right side up neither: graph looks same above xaxis as it does below asymptotes: y=b horizontal,
=b or
=b, vertical asymptote x=a
inverse: original, then solve for x,switch x and y. translations: horizontal: 1.
a translation to the right by c units
2.
a translation to the left by c units
3. across the xaxis 4. stretches and shrinks
a stretch by a factor of c if c>1, shrink by a factor of c if c<1
Vertical
1.
a translation up
2.
a translation down
3. across the yaxis
, for range: graph
4.
equations: : circumferenc of circle simple interest I=Prt compound interest A=P(1+r/n)^nt
Chapter 2
polynomial function: where n is degree, and a is leading coefficient, an vertex form of a quad func: f(x)=a(xh)^2+k (h,k) axis x=h, where h=b/2a and k=cah^2 if