11.
A. mean=2
B. median =2
C. sum of squared deviations= 22
D. variance=2
E. standard deviation=1
12.
A. mean= 1312
B. median= 1361
C. sum or squared deviations= 31,0674
D. variance= 6253
E. standard deviation= 79
13.
A. mean= 3.2
B. median= 3.25
C. sum or squared deviations= -1.46
D.variance= -.24
E. standard deviations= .49
14.
A. mean= 1
B. median=7
C. sum or squared deviations= 67
D. variance= 11.2
E. standard deviation=3.3
21. Participants saw a picture of either a gun or a tool and they were told to push a certain button on the computer for either picture they saw. The participant didn’t know but each picture had a certain race. For instance, the gun picture showed a black male and the tool picture showed a white male. This experiment shows that when people had to choose as fast as they could they did chose the black male to have a gun and the tool over a white male. This was not a significant difference, only 3 more black male was chosen over the white male.
Ch. 3, Practice Problems: 14, 15, 22, & 25
14.
a.) z = [(340) - (300)] / (20) z = 2
b.) z = [(310) - (300)]/(20) z score = 0.5
Raw Score
a.) z = 2.4
2.4 = (x-300)/20
(2.4) * 20 + 300 = x
raw score = 348
b.) z = 1.5
1.5 = (x- 300) /20
raw score = 330
15. Standard deviation is defined as a number calculated to show the extent of deviation for a whole group of people. In this verbal test, the person scored an 81 on a test when the standard deviation was 20. 20 is the average score and this person scored way above the normal range. In the quantitative test the standard deviation was 5 and the person scored a 6.4. This is