Emission Spectroscopy Post Lab Questions

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Emission Spectroscopy Post Lab Questions
CHEM 053

1. For two of your sparklers, write a short paragraph presenting & discussing your data and observations. You should include identification and discussion of the cations determined to be present
Answer:

2. The nightlight you investigated is considered an RGB-mixing LED, capable of producing millions of different color variations.
a. What wavelengths of light did you observe in the colors of the nightlight (use a table to organize your data)? Which colors had one peak? Two peaks? Three peaks?
Answer:
Color Wavelength (nm) Intensity (rel)
Green 514.1 0.157
Blue 450.8 0.345
Yellow (Peak 1)
Yellow (Peak 2) 514.1
628.3 0.157
0.164
Teal (Peak 1)
Teal (Peak 2) 451.6
514.1 0.263
0.136
Purple (Peak …show more content…
Yellow, teal, and purple had two peaks. White had three peaks.
b. What happened to the peaks as the nightlight faded from one color to the next.
Answer: At times, the peak would disappear completely. Some peaks would also get lower as their intensity decreased while the peaks at another wavelength would get higher as the intensity increased.
c. Use your data to predict how pink could be created on this nightlight.
Answer: Pink would be created on this nightlight by mixing the wavelengths of red and white.

3. Potassium gluconate (K+C6H11O7¯) produces a light purple flame. Copper(II) sulfate (Cu2+SO42¯) produces a green flame. What flame color would you expect for copper(II) gluconate (Cu2+[C6H11O7¯]2)? Explain.
Answer: I would expect the flame to be green color like the copper (II) sulfate. The potassium in potassium gluconate and the copper in copper (II) sulfate are what emit the visible light when lit by a flame. However, potassium is not present in copper(II) gluconate, so the copper is the only cation left to emit its color. Because of this, the flame will be green.

4. In lab, we used the Rhydberg Equation to predict the wavelengths of visible light to be observed for the emission hydrogen
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