Essay On Static Friction

Submitted By zactran98
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Tran, Nhat (Zac)
Period 7
IB Physic SL
October 27th, 2014
Static and Kinetic Friction Data collection
Data Table 1: peak static friction
Total mass (kg) ± .0005
Normal force (N) ± .01
Average peak static fiction (N) ± .001
s ± .0003- .0006
1.084
10.84
2.950
.2721
1.284
12.84
3.659
.2849
1.484
14.84
4.052
.2730

*Caption: These are data I collected from the experiment, which includes mass of the object (1.084kg, 1.284kg, and 1.484g), the normal force of each mass, peak friction of each mass, and static coefficient of friction of each mass (calculation will be shown in the ‘data processing and presentation’ section). *Brief explanation: The normal force of the mass is equal in magnitude and opposite in direction to the gravitational force (Fn= Fg= mg). After I got the normal force, I took the static friction (obtained from the peak of the graph) divided by normal force to get the static coefficient of friction.

Data Table 2: kinetic friction
Total mass (kg) ± .0005
Normal force (N) ± .01
Average kinetic friction (N) ± .001
k ± .0002-.0003
1.084
10.84
1.993
.1948
1.284
12.84
2.575
.2005
1.484
14.84
3.013
.2098

*Caption: These are data I collected from the experiment, which includes mass of the object (1.084kg, 1.284kg, and 1.484g), the normal force of each mass, kinetic friction of each mass, and kinetic coefficient of friction of each mass(calculation will be shown in the ‘data processing and presentation’ section). *Brief explanation: The normal force of the mass is equal in magnitude and opposite in direction to the gravitational force (Fn= Fg= mg). After I got the normal force, I took the kinetic friction (obtained from the constant section of the graph) divided by normal force to get the kinetic coefficient of friction.

Data table 3: kinetic friction (block with additional mass)
Trial
Acceleration (m/s^2) ± .001
Kinetic friction force (N) ± .004- .007
k ± .005-.008
1
5.309
.2577
.3067
2
5.214
.2799
.3332
3
5.542
.2031
.2939
Average coefficient of kinetic friction
.2939
*Caption: These are data I collected from the experiment, which includes the acceleration of the block (without additional mass), the kinetic friction force, and the kinetic coefficient of friction (calculation will be shown in the ‘data processing and presentation’ section). *Brief explanation: By assuming that the tension and acceleration are the same for both mass one and mass two, we can calculate tension for mass two and use it to calculate kinetic friction for mass one; the kinetic coefficient of friction will then by deprived from the equation k= Fk/ Fn.

Data table 4: kinetic friction (block with additional mass)
Trial
Acceleration (m/s^2) ± .001
Kinetic friction force (N) ± .01-.02
k ± .006- .009
1
1.291
1.0689
.5809
2
1.303
1.0648
.5787
3
1.316
1.0605
.5764
Average coefficient of kinetic friction
.5787
*Caption: These are data I collected from the experiment, which includes the acceleration of the block (with additional mass +100g), the kinetic friction force, and the kinetic coefficient of friction (calculation will be shown in the ‘data processing and presentation’ section). *Brief explanation: By assuming that the tension and acceleration are the same for both mass one and mass two, we can calculate tension for mass two and use it to calculate kinetic friction for mass one; the kinetic coefficient of friction will then by deprived from the equation k= Fk/ Fn. Comparing this data table to data table number 3, we can see the kinetic friction and the kinetic coefficient of friction increase when additional mass is added to the block while the second mass is kept the same.

*Caption: This is a free body diagram demonstrating all the force applied on the block as the falling objective pulls the block down. The pulley is used to direct the force of the block.

Data Processing and presentation
Data table 1:
1st
 Fn= 10.84 N
 s = 2.950/ 10.84
 s = .2721 ± .0003
2nd
 Fn= 12.84 N
 s =
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