Hydrogen Gas Lab Essay

Submitted By Melissa-Botelho
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Pages: 5
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Measuring and Reporting the Molar Volume of Hydrogen Gas

Melissa Botelho
SCH3UB
Mrs.Mascherin
January 16, 20

Purpose:
To produce and collect hydrogen gas by reacting magnesium and hydrochloric acid. To use stoichiometry to calculate the molar volume of hydrogen at room temperature and pressure and compare this value to accepted values.

Materials:
Thermometer
Ring stand
Burette clamp
Gas-measuring tube (50cm3)
Funnel
Graduated cylinder (25cm3)
Beaker (400 cm3)
One hole stopper
Deep glass container(1000cm3)
Metric ruler
Copper wire (20cm)
Room temperature water
Safety goggles
2 cm magnesium ribbon
10 cm3 of 6 mol/dm3 hydrochloric acid

Procedure:
Refer to lab sheet “Measuring and Reporting the Molar Volume of Hydrogen Gas”

Observations:
Table 1: Qualitative Observations- Molar Volume of Hydrogen Gas
Reactant
Physical Properties
Chemical Properties
HCl
Strong smell
No characteristic feeling
Clear liquid with a yellow tint due to high concentration
A reaction between hydrochloric acid and magnesium resulted in a single displacement reaction, the products being magnesium chloride ( MgCl2) and hydrogen gas (H2). As hydrochloric acid and magnesium react, bubbles of gas are formed. Once the reaction is complete the gas rises to the top of the gas measuring tube and displaces the water in the tube.
Magnesium
Silver
Malleable
Conducts electricity
Ductile

Data Processing:
Table 2: Data collection- Molar Volume of Hydrogen Gas
Room Temperature
294K
Room Pressure
102.7 kPa
Mass of 2 cm of Magnesium Ribbon

= = 2.86 g/cm 0.0735 g/cm x= x=0.0286gg

Volume of H2 gas
27.8 cm3 cm3
Volume of 6 M HCl
10.00.05 cm3

1. Write the balanced chemical equation for the reaction and place all given information below the appropriate species:
Mg(s) + 2HCl(aq)  MgCl2(aq) + H2 m =0.0286gg v= 0.01dm3 5x10-5 dm3 V=0.0328L 5x10-5L
T=294K T=294K
P=102.7kPa P=102.7kPa

2. Determine the number of moles of magnesium used in the reaction

n= = =1.176954733 x 10-3 mol 3. 083539096 x 10 -5 mol

3. Determine the number of moles of hydrogen gas produced
We are told that HCl is in excess, therefore Mg is the limiting reactant
MR : 1.176954733 x 10-3 mol 3.083539096 x 10 -5 mol of H2 is produced

4. Determine the Molar Volume of Hydrogen gas
Vm = = =23.62027971 dm3/mol 0.6613173282 dm3/ mol
The molar volume of Hydrogen gas is 23dm3/mol 0.6613173282 dm3/ mol

Conclusion: In this experiment, 10cm3 of 6 mol/dm3 hydrochloric acid solution was placed into a gas measuring tube, and then the tube was filled with water. Two centimeters of magnesium ribbon was suspended in the gas measuring tube by a piece of copper wire. A stopper with a hole was placed on top of the gas measuring tube and the tube was placed upside down in a beaker of water. The magnesium reacted with excess hydrochloric acid to from hydrogen gas and magnesium chloride. The reaction was observed until bubbles no longer form, once the reaction ended, the gas measuring tube was removed from the beaker and placed into a beaker with room temperature water. The pressure in the gas measuring tube was thus adjusted to room pressure. It was observed that the volume of hydrogen gas produced in the reaction was 27.8 cm3 cm3. Using stoichiometry and gas laws, the molar volume of hydrogen gas produced could be determined. Dividing the mass of magnesium used by its molar mass, it was deduced that 1.176954733 x 10-3 mol 3. 083539096 x 10 -5 mol of magnesium was used in the reaction. Using the balanced equation of the reaction a mol ratio between magnesium and hydrogen gas proved that 1.176954733
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