T=D/V and V= H0D
First, we are given the equation above that states that Time (T) = Distance (D) over Velocity (V), which is a universal law that can help us to determine the age of the universe that is derived …show more content…
T=1/Ho
Then we canceled out both distances to give us the equation above as the root to find the age of the universe.
Ho=((68 km/s)/mpc) , T=(((1/68km)/s)/mpc)
In the prompt we are also given the value of H0 that can substitute H0 in our time equation. 1 mpc=3.086x1022 m, T=((1/68km)/s)/(3.086⋅〖10〗^26 m)
Finally, the prompt gave us the distance equivalent to 1 megaparsecs, which is an unit of distance that is used to measure the distance between stars. This number can then subsitute the mpc in our time equation.
68 km* (1000m/1km)= 68000m
However, since there is kilometers and meters in this equation we must convert the kilometers into meters in order to be consistent. We do this conversion by multiplying 68 by 1000 since there are 1000 meters in one …show more content…
To start, we transform seconds into minutes (min) by dividing your time by 60, since there are 60 seconds in a minute. We also cancel out both seconds only leaving us with minutes
T= 7.565x10^15 min*1h/60min= 1.2608x10^14 h
Next, we do the same thing but converting minutes to hours (h) by dividing our minutes by 60 since there are 60 minutes in an hour. Also canceling out minutes leaving the hours.
T= 1.2608x10^14 h *1d/24h =5.254x10^12 d
Next, we do the same step by converting hours to days (d) by diving our time by 24 since there are 24 hours in a day and then we canceled out the hours leaving days as the unit.
T= 5.254x 10^12 d *1y/365d= 1.439x10^10 y
For the last step we take the days we convert the days into years (y) by dividing by 365, since there are 365 days in a year and canceled out the days with days leaving with years. That left us with our final approximation of the age of the universe…
14,390,000,000 years or 14.39 billion